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1/x^2-3x+2+1/x^2-4x+3=1/x^2-5x+6
We move all terms to the left:
1/x^2-3x+2+1/x^2-4x+3-(1/x^2-5x+6)=0
Domain of the equation: x^2!=0
x^2!=0/
x^2!=√0
x!=0
x∈R
Domain of the equation: x^2-5x+6)!=0We add all the numbers together, and all the variables
x∈R
-7x+1/x^2+1/x^2-(1/x^2-5x+6)+5=0
We get rid of parentheses
-7x+1/x^2+1/x^2-1/x^2+5x-6+5=0
We multiply all the terms by the denominator
-7x*x^2+5x*x^2-6*x^2+5*x^2+1+1-1=0
We add all the numbers together, and all the variables
-1x^2-7x*x^2+5x*x^2+1=0
Wy multiply elements
-1x^2-7x^3+5x^3+1=0
We do not support expression: x^3
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